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Stupid Question - Web Scripting - How do you address a remote PC?
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sinc747  
#1 Posted : Tuesday, February 16, 2021 4:53:06 AM(UTC)
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I am using the vMix Script Builder from our friends at Studio 793 to build some simple Web Scripts for a project. But I cannot figure out how to address a 2nd PC with a Web Script. Do you know?

TIA!

- Tom
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doggy  
#2 Posted : Tuesday, February 16, 2021 8:41:43 AM(UTC)
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sinc747  
#3 Posted : Tuesday, February 16, 2021 4:01:47 PM(UTC)
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Originally Posted by: doggy Go to Quoted Post
HTTP webrequest

https://forums.vmix.com/...ng-for-Dummies#post70833


Thanks, but not sure what I'm looking for in the forum thread.

- Tom
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rudyengels  
#4 Posted : Tuesday, February 16, 2021 4:38:56 PM(UTC)
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doggy  
#5 Posted : Tuesday, February 16, 2021 5:17:20 PM(UTC)
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Originally Posted by: sinc747 Go to Quoted Post
Originally Posted by: doggy Go to Quoted Post
HTTP webrequest

https://forums.vmix.com/...ng-for-Dummies#post70833


Thanks, but not sure what I'm looking for in the forum thread.

- Tom




This Part Tom

Code:
'HTTP
Dim client = WebRequest.Create("http://127.0.0.1:8088/api/?Function=SetText&Input=Title 0- The Classic Blue.gtzip&SelectedName=Headline.Text&Value=Some Text")
Dim response = client.GetResponse()
response.Close

replace IP to 2nd pc's
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sinc747  
#6 Posted : Wednesday, February 17, 2021 3:56:19 AM(UTC)
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Thanks Rudy & Doggy! That's what I needed.

Now... how can I add a 2nd command to the same script.

So far I have

Dim client = WebRequest.Create("http://192.168.1.25:8088/api/?Function=VideoCallAudioSource&Input=Call 2349873452&Value=BusG")
Dim response = client.GetResponse()
response.Close

I want to add a 2nd command to the same PC...
Function = VideoCallVideoSource
Input = Call 2349873452
Value = Output2

What is the syntax for a 2nd command in the same script?

Again, thank you!

- Tom
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doggy  
#7 Posted : Wednesday, February 17, 2021 9:18:40 PM(UTC)
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Originally Posted by: sinc747 Go to Quoted Post
Now... how can I add a 2nd command to the same script.



Guess something like this might work

Code:
Dim client as WebRequest = WebRequest.Create("http://127.0.0.1:8088/api/?Function=SetText&Input=Title 0- The Classic Blue.gtzip&SelectedName=Headline.Text&Value=Some Text")
Dim response As WebResponse = client.GetResponse()

sleep(1000)

client = WebRequest.Create("http://127.0.0.1:8088/api/?Function=SetText&Input=Title 0- The Classic Blue.gtzip&SelectedName=Headline.Text&Value=other Text")
response = client.GetResponse()
response.Close

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Peter1000  
#8 Posted : Thursday, February 18, 2021 1:05:59 AM(UTC)
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I was getting errors, not closing the connection after every command. I would suggest to close the connection after every webrequest.
I also believe that you can send a second command faster than waiting a second. Try it out.

Code:
Dim client as WebRequest = WebRequest.Create("http://127.0.0.1:8088/api/?Function=SetText&Input=Title 0- The Classic Blue.gtzip&SelectedName=Headline.Text&Value=Some Text")
Dim response As WebResponse = client.GetResponse()
response.Close

sleep(1000)

client = WebRequest.Create("http://127.0.0.1:8088/api/?Function=SetText&Input=Title 0- The Classic Blue.gtzip&SelectedName=Headline.Text&Value=other Text")
response = client.GetResponse()
response.Close
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doggy  
#9 Posted : Thursday, February 18, 2021 1:24:51 AM(UTC)
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Originally Posted by: Peter1000 Go to Quoted Post
I was getting errors, not closing the connection after every command. I would suggest to close the connection after every webrequest.
I also believe that you can send a second command faster than waiting a second. Try it out.



The sleep time was just a way for the example (setting a text in a title ) for the change to be visible when running the script !

FYI: i was not getting an error omitting the first close , but it of course never hurts
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sinc747  
#10 Posted : Friday, February 19, 2021 11:01:58 AM(UTC)
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Awesome Baby!

Thank you.

- Tom
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